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  4. The acceleration of a certain simple harmonic oscillator is given by a=-(35.28 m / s 2) cos 4.2 t. The amplitude of the simple harmonic motion is :

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Q. The acceleration of a certain simple harmonic oscillator is given by $a=-\left(35.28 m / s ^{2}\right) \cos 4.2 t$. The amplitude of the simple harmonic motion is :

Oscillations

Solution:

Given $\omega^{2} A=35.28$
$\omega=4.2$
$\Rightarrow A=\frac{\omega^{2} A}{(\omega)^{2}}=\frac{35.28}{(4.2)^{2}}=2.0 \,m $