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Q. The acceleration of a body due to the attraction of the earth (radius $R$ ) at a distance $2R$ from the surface of the earth is $\left(\right.g=$ acceleration due to gravity at the surface of the earth)

NTA AbhyasNTA Abhyas 2020

Solution:

$g^{'}=g\left(\frac{R}{R + h}\right)^{2}=g\left(\frac{R}{R + 2 R}\right)^{2}=\frac{g}{9}$