Question

The acceleration of a body due to attraction of the earth (radius $R$ ) at a distance $2R$ from the surface of the earth is ( $g=$ acceleration due to gravity at the surface of the earth)

• A. $\frac{g}{9}$
• B. $\frac{g}{3}$
• C. $\frac{g}{4}$
• D. $g$

Answer 1

Answer: (A)

$g′=\frac{g R^{2}}{\left(R + h\right)^{2}}$
$g′=\frac{g R^{2}}{\left(R + 2 R\right)^{2}}$
$g′=\frac{g R^{2}}{\left(3 R\right)^{2}}$
$g′=\frac{g}{9}$