1. Tardigrade
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  3. Physics
  4. The acceleration due to gravity on the surface of moon is 1.7 m s -2 What is the time period of a simple pendulum. on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s -2)

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Q. The acceleration due to gravity on the surface of moon is $1.7\, m\, s ^{-2} $ What is the time period of a simple pendulum. on the surface of moon if its time period on the surface of earth is $3.5 \,s$ ? (g on the surface of earth is $9.8 \,m \,s ^{-2})$

Oscillations

Solution:

Here, $g_{m}=1.7 \,m\, s ^{-2}, g_{e}=9.8\, m \,s ^{-2}, T_{e}=3.5\, s$
As $T_{e}=2 \pi \sqrt{\frac{l}{g_{e}}} $
and $T_{m}=2 \pi \sqrt{\frac{l}{g_{m}}}$
$\therefore \frac{T_{m}}{T_{e}}=\sqrt{\frac{g_{e}}{g_{m}}}$
or $T_{m}=T_{e} \sqrt{\frac{g_{e}}{g_{m}}}=3.5$
$ \sqrt{\frac{9.8}{1.7}}=8.4\, s$