The absolute value of enthalpy of neutralization of this reaction is greater than $-57.33 kJ mol ^{-1}$.
This is due to the very high enthalpy of hydration of $Mg ^{2+}$ ion. The change in enthalpy of this reaction is nearly $-146 kJ$.
Thus enthalpy of neutralization per mole of $H ^{+}$ion is nearly $-73 kJ$, which is greater than the enthalpy of neutralization strong acid against strong base i.e. $-57.33 kJ$.