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Q.
The abscissa(e) of the point(s), where the tangent to curve $y=x^{3}-3x^{2}-9x+5$ is parallel to the $x$ -axis is(are)
NTA AbhyasNTA Abhyas 2020Application of Derivatives
Solution:
$y=x^{3}-3x^{2}-9x+5$
$\Rightarrow $ $\frac{d y}{d x}=3x^{2}-6x-9$
We know that this equation gives the slope of the tangent to the curve. The tangent is parallel to $x$ -axis.
Therefore, $3x^{2}-6x-9=0$
$\Rightarrow \, $ $x=-1, \, 3$ .