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Q. The $71^{st}$ electron of an element $X$ with an atomic number of $71$ enters into the orbital :

JEE MainJEE Main 2019Classification of Elements and Periodicity in Properties

Solution:

Electronic Configuration of Element X with atomic number 71 is $[ Xe ] 4 f ^{14} 6 s ^{2} 5 d ^{1}$.
The Last electron will enter in $5 d$ orbital.