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  4. The 25 mL of a 0.15 M solution of lead nitrate, Pb ( NO 3)2 reacts with all of the aluminium sulphate, Al 2( SO 4)3, present in 20 mL of a solution. What is the molar concentration of the Al 2( SO 4)3 ? 3 Pb ( NO 3)2( aq )+ Al 2( SO 4)3( aq ) longrightarrow 3 PbSO 4( s )+2 Al ( NO 3)3( aq )

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Q. The $25 \,mL$ of a $0.15 \, M$ solution of lead nitrate, $Pb \left( NO _{3}\right)_{2}$ reacts with all of the aluminium sulphate, $Al _{2}\left( SO _{4}\right)_{3}$, present in $20 \,mL$ of a solution. What is the molar concentration of the $Al _{2}\left( SO _{4}\right)_{3}$ ?
$3 Pb \left( NO _{3}\right)_{2}( aq )+ Al _{2}\left( SO _{4}\right)_{3}( aq ) \longrightarrow 3 PbSO _{4}( s )+2 Al \left( NO _{3}\right)_{3}( aq )$

BITSATBITSAT 2018

Solution:

Molar mass of $Pb \left( NO _{3}\right)_{2}=25 \times 0 \cdot 15$
$=3.75\, m$. moles
Molar mass of $Al _{2}\left( SO _{4}\right)_{3}$
$=\frac{1}{3} \times 3 \cdot 75= M \times 20$
$M=0.0625=6.25 \times 10^{-2} M$