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Q. The 10th term of the sequence $\sqrt3,\sqrt{12}, \sqrt{27}......... $ is

Sequences and Series

Solution:

$\sqrt{3},\sqrt{12}, \sqrt{27},.....$ can be written as
$ \sqrt{3.1}, \sqrt{3.4}, \sqrt{3.9}, ..... $
i.e., $\sqrt{3.1^{2}} , \sqrt{3.2^{2}}, \sqrt{3.3^{2}} , ..... $
$ \therefore 10$th term $= \sqrt{3.10^{2}} $
$= \sqrt{300}$