Q. tert-butyl methyl ether on heating with anhydrous HI in ether gives
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Solution:
Here, ether is the solvent. Being less polar, it favours $ {{\text{S}}_{\text{N}}}\text{2} $ reaction and the nucleophile $ {{\text{I}}^{-}} $ attacks the $ {{\text{1}}^{\text{o}}} $ carbon of $ \text{C}{{\text{H}}_{3}}. $