Thank you for reporting, we will resolve it shortly
Q.
Tension in the rope at the rigid support is $\left(g=10\, m / s ^{2}\right)$
Laws of Motion
Solution:
For $40\, kg$
$400-T_{1}=40(1)$
$T_{1}=360\, N$
for $50\, kg$
$500+T_{1}-T_{2}=50(2)$
$\Rightarrow T_{2}=760\, N$
for $60\, kg \Rightarrow T_{3}-600-T_{2}=60$ (2)
$T_{3}=1580\, N$
$T_{3}$ will be the tension at the topmost point on the rigid support.
