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Chemistry
Temperature at which r.m.s. speed of O2 is equal to that of neon at 300 K is:
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Q. Temperature at which r.m.s. speed of $O_{2}$ is equal to that of neon at $300\, K$ is:
States of Matter
A
$280\, K$
100%
B
$480\, K$
0%
C
$680\, K$
0%
D
$180\, K$
0%
Solution:
$U_{rms}=\sqrt{\frac{T}{M_{w}}} T \propto M_{w}$
$\frac{T_{Ne}}{T_{o_2}}=\frac{20}{32}$
$T_{o_2}=480\,K$