Question

Switch is in position $A$ for long time. At time $t=0$ it is shifted to position $B$. Find the maximum charge that will accumulate on capacitor

• A. $(\sqrt{L C}) \frac{E}{R}$
• B. $\frac{E}{(\sqrt{L C}) R}$
• C. $\left(\sqrt{\frac{L}{C}}\right) \frac{E}{R}$
• D. $\left(\sqrt{\frac{C}{L}}\right) \frac{E}{R}$

Answer 1

Answer: (A)

$I_{\max }=\omega_{0} q_{\max }$
$I_{\max }=\frac{\varepsilon}{R}$
$\omega_{0}=\frac{1}{\sqrt{L C}}$
$q_{\max }=\frac{E / R}{1 / \sqrt{L C}} $
$\Rightarrow q_{\max }=(\sqrt{L C}) \frac{E}{R}$