1. Tardigrade
  2. Question
  3. Biology
  4. Suppose the three non-linked autosomal genes A , B and C control coat colour in an animal and the dominants alleles A , B and C are responsible for dark colour and the recessive alleles a, b and care responsible for light colour. If a cross between a male of AABBCC genotype and a female of aabbcc genotype produces 640 offsprings in the F2- generation, how many of them are likely to be of the parental genotype?

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Suppose the three non-linked autosomal genes A , B and C control coat colour in an animal and the dominants alleles A , B and C are responsible for dark colour and the recessive alleles a, b and care responsible for light colour. If a cross between a male of AABBCC genotype and a female of aabbcc genotype produces 640 offsprings in the $F_{2-}$ generation, how many of them are likely to be of the parental genotype?

KVPYKVPY 2017

Solution:

In a Mendelian trihybrid cross between $A A B B C C$ and aabbcc parents the $F _{2}$ progenies produced are $640 .$
$\therefore $ The number of parental combinations
$=\frac{2}{64} \times 640=20$