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Q. Suppose refractive index $\mu$ is given as $\mu=A+\frac{B}{\lambda^{2}}$, where $A$ and $B$ are constants and $\lambda$ is wavelength then the dimensions of $B$ are same as that of

AMUAMU 2005

Solution:

We know that energy equation relating physical quantity should be in dimensional balance.
Hence, dimensions of terms on both sides of given equation must be same.
Given, $ \mu=A+\frac{B}{\lambda^{2}}$
where refractive index is a dimensionless quantity,
hence $\frac{B}{\lambda^{2}}$ is also dimensionless
$\therefore $ Dimension of $B=$ dimension of $\lambda^{2}$
$= cm ^{2}$
$=$ dimensions of area