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Q.
Sum of the two binary numbers $(100010)_{2}$ and $(11011)_{2}$ is
Bihar CECEBihar CECE 2007Semiconductor Electronics: Materials Devices and Simple Circuits
Solution:
Binary numeral system is also known as base $2$ numerals.
The given number is first converted from binary to decimal equivalence
$(100010)_{2}=2^{5} \times 1+2^{4} \times 0+2^{3} \times 0+2^{2} \times 0+2^{1} \times 1+2^{o} \times 0$
$=32+0+0+2+0$
$=(34)_{10}$
and $(11011)_{2}=2^{4} \times 1+2^{3} \times 1+2^{2} \times 0+2^{1} \times 1 \times 2^{o} \times 1$
$=16+8+0+2+1$
$=(27)_{10}$
$\therefore $ Sum $(100010)_{2}+(11011)_{2}$
$=(34)_{10}+(27)_{10}$
$=(61)_{0}$
Now,
$\therefore $ Required sum (in binary system)
$(100010)_{2}+(11011)_{2}=(111101)_{2}$
