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Q.
Sulphuryl chloride, $SO_2Cl_2$, reacts with $H_2O$ to give mixture of $H_2SO_4$ and HCl. Aqueous solution of 1 mol $SO_2Cl_2$ will be neutralised by
Some Basic Concepts of Chemistry
Solution:
$\underset{1 mol }{ SO _2 Cl _2}+\underset{2 mol }{2 H _2 O } \rightarrow \underset{1 mol }{ H _2 SO _4}+\underset{2 mol }{2 HCl }$
$H _2 SO _4+2 \underset{2 mol }{ NaOH } \rightarrow Na _2 SO _4+ H _2 O$
$\underset{1 mol }{ HCl }+\underset{1 mol }{ NaOH } \rightarrow NaCl + H _2] \times 2$
$\therefore 1$ mol of $SO _2 C l_2$ in aq. solution requires
4 mol of $NaOH$ or 2 mol of $Ca ( OH )_2$