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Chemistry
Sulphide ore on roasting gives a gas X. X reacts with Cl2 in the presence of activated charcoal to give Y. Y is:
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Q. Sulphide ore on roasting gives a gas $X$. $X$ reacts with $Cl_2$ in the presence of activated charcoal to give $Y$. $Y$ is:
KCET
KCET 2020
General Principles and Processes of Isolation of Elements
A
$SO_2Cl_2$
58%
B
$S_2Cl_2$
11%
C
$SCl_6$
9%
D
$SOCl_2$
23%
Solution:
The corresponding reactions are;
$2 Cu _{2} S +3 O _{2} \rightarrow 2 Cu _{2} O +2 SO _{2}( s )$ (Reaction involved in roasting)
$SO _{2}+ Cl _{2}+$ activatedcharcoal $\rightarrow SO _{2} Cl _{2}$
So here $X$ is $SO _{2}$ (sulphur dioxide)
And $Y$ is $SO _{2} Cl _{2}$ (Sulfuryl chloride)