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Q. Sulphide ore on roasting gives a gas $X$. $X$ reacts with $Cl_2$ in the presence of activated charcoal to give $Y$. $Y$ is:

KCETKCET 2020

Solution:

The corresponding reactions are;

$2 Cu _{2} S +3 O _{2} \rightarrow 2 Cu _{2} O +2 SO _{2}( s )$ (Reaction involved in roasting)

$SO _{2}+ Cl _{2}+$ activatedcharcoal $\rightarrow SO _{2} Cl _{2}$

So here $X$ is $SO _{2}$ (sulphur dioxide)

And $Y$ is $SO _{2} Cl _{2}$ (Sulfuryl chloride)