1. Tardigrade
  2. Question
  3. Chemistry
  4. Sulphide ion (S2-) reacts with solid sulphur forming S2-2 and S2-3 with formation constants 12 and 132 respectively. Formation constant of S2-3 from sulphur and S2-2 is :

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Q. Sulphide ion $(S^{2-})$ reacts with solid sulphur forming $S^{2-}_2$ and $S^{2-}_3$ with formation constants 12 and 132 respectively. Formation constant of $S^{2-}_3$ from sulphur and $S^{2-}_2$ is :

Equilibrium

Solution:

(l) $S ^{2-}+ S \rightleftharpoons S _2^{2-} ; K _1=12$
(II) $S ^{2-}+ S \rightleftharpoons S _3^{2-} ; K _1=132$
(III) $S _2^{2-}+ S \rightleftharpoons S _3^{2-} ; K =$ ?
To get eqn. (III), subtract (I) from (II)
$K =\frac{K_2}{K_1}=\frac{132}{12}=11$