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  4. Stock phosphoric acid solution is 85 % H 3 PO 4 (by mass of solution) and has a specific gravity of 1.70. Hence, molarity of H 3 PO 4 solution is

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Q. Stock phosphoric acid solution is $85 \% H _3 PO _4$ (by mass of solution) and has a specific gravity of $1.70$. Hence, molarity of $H _3 PO _4$ solution is

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Solution:

$100\, g \,H _3 PO _4$ solution has $=85\, g \,H _3 PO _4$
$\frac{100}{1.7} mL H _3 PO _4$ solution has $=85 \,g\, H _3 PO _4$
$=\frac{85}{98}$ mol
$\therefore$ Molarity $=\frac{85 / 98 mol }{\left(\frac{100}{1.7 \times 1000} L \right)}=14.74 \,M$