1. Tardigrade
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  4. Steam at 100 °C is passed into 1 kg of water contained in a calorimeter at 9 °C till the temperature of water and calorimeter is increased to 90 °C. The mass of the steam condensed is nearly (Water equivalent of calorimeter = 0.1 kg Specific heat of water = 1 calg-1 °C-1 Latent heat of vapourisation = 540 calg-1)

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Q. Steam at $100 {^{\circ}C}$ is passed into $1\, kg$ of water contained in a calorimeter at $9 {^{\circ}C}$ till the temperature of water and calorimeter is increased to $90 {^{\circ}C}$. The mass of the steam condensed is nearly
(Water equivalent of calorimeter $= 0.1\, \, kg$
Specific heat of water $= 1 \, calg^{-1} {^{\circ}C^{-1}}$
Latent heat of vapourisation $= 540 \, calg^{-1}$)

AP EAMCETAP EAMCET 2018

Solution:

Let mass of the steam condensed is $x$.
Heat released $=$ Heat gained by water
$\Rightarrow x \times 540+x \times 1 \times(100-90)$
$=1 \times 1 \times(90-9)+0.1 \times 1 \times(90-9)$
$\Rightarrow 540 x+10 x=81+8.1$
$\Rightarrow x=\frac{89.1}{550}=0 .162\, kg , x=162\, g$