1. Tardigrade
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  3. Physics
  4. Steam at 100 ° C is passed into 1.1 textkg of water contained in a calorimeter of water equivalent 0.02 textkg at 15 ° C , till the temperature of the calorimeter and its contents rises to 80 text °C text. The mass of steam condensed (in kg ) is (. Take latent heat of steam = 540 cal g- 1) :

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Q. Steam at $100 \, ^\circ C$ is passed into $1.1 \, \, \text{kg}$ of water contained in a calorimeter of water equivalent $0.02 \, \, \text{kg}$ at $15 \, ^\circ C$ , till the temperature of the calorimeter and its contents rises to $80\text{ °}C\text{.}$ The mass of steam condensed (in $kg$ ) is
$\left(\right.$ Take latent heat of steam $= \, 540 \, cal \, g^{- 1})$ :

NTA AbhyasNTA Abhyas 2022

Solution:

Heat release by steam = Heat gained by calorimeter and its contents
Solution

Solution
$1.12\times \left(80 - 15\right)=m\times 540+m\times 20$
$m=0.130 \, kg$