Q.
Statement I Power of a lens is defined as $p=1 / f$, $f=$ focal length.
Statement II A lens of a high power has large focal length.
Ray Optics and Optical Instruments
Solution:
A lens with large focal length have less power.
i.e., $P \propto \frac{1}{f} $
or $f \propto \frac{1}{P}$
