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Q. Statement I Power of a lens is defined as $p=1 / f$, $f=$ focal length.
Statement II A lens of a high power has large focal length.

Ray Optics and Optical Instruments

Solution:

A lens with large focal length have less power.
i.e., $P \propto \frac{1}{f} $
or $f \propto \frac{1}{P}$

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