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Q. Statement I: Potential measured by a voltmeter across a wire is always less than the actual potential difference across it.
Statement II: Finite resistance of voltmeter changes current flowing through the resistance across which potential difference is to be measured.

Current Electricity

Solution:

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$ i_{1}=\frac{E}{R} R_{ eq }=\frac{R R_{V}}{R+R_{\nu}} $
$ i_{2}=\frac{E}{\left(R R_{V} / R+R_{V}\right)} $