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Q. Statement I : Molecular mass of cane sugar $\left( C _{12} H _{22} O _{11}\right)$ is $182\, amu$.
Statement II : 1 mole of cane sugar contains $6.022 \times 10^{23}$ molecules of cane sugar.

Some Basic Concepts of Chemistry

Solution:

Molecular mass of cane sugar $\left( C _{12} H _{22} O _{11}\right)$
$=12 \times 12+22 \times 1+11 \times 16$
$=342 \,amu$
$1$ mole of cane sugar $\left( C _{12} H _{22} O _{11}\right)=342 \, g$
(Molecular mass of cane sugar $=342 \,g$ )
$342 \,g$ of cane sugar contain $=6.022 \times 10^{23}$ molecules