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Q. Statement-I: If $11x - 9 \le 68$, then $x\in \left(-\infty,\,7\right)$.
Statement-II: If an inequality consist of signs $\le$ or $\ge$, then the point on the line are also included in the solution region.

Linear Inequalities

Solution:

We have, $11x - 9 \le 68$
$\Rightarrow \quad11x \le 77 \Rightarrow x \le\quad\therefore \quad 7x\in \left(-\infty,\,7\right)$
So, statement-I is false but statement-II is true.