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Q. Statement I Every differentiable function is continuous but converse is not true.
Statement II Function $f(x)=|x|$ is continuous.

Continuity and Differentiability

Solution:

In above solution we have proved that, every differentiable function is continuous.
But the converse of the above statement is not true. We know that, $f(x)=|x|$ is a continuous function. Consider the left hand limit
$\displaystyle\lim _{h \rightarrow 0^{-}} \frac{f(0+h)-f(0)}{h}=\frac{-h}{h}=-1$
The right hand limit
$\displaystyle\lim _{h \rightarrow 0^{+}} \frac{f(0+h)-f(0)}{h}=\frac{h}{h}=1$
image
Since, the above left and right hand limits at 0 are not equal. $\displaystyle\lim _{h \rightarrow 0} \frac{f(0+h)-f(0)}{h}$ does not exist and hence $f$ is not differentiable at 0 . Thus, $f$ is not a differentiable function.