Question

Statement (A)Sulphur vapour is paramagnetic.
Statement (B) Reaction of dil. HCl with finely divided iron forms $FeCl _{3}$ and $H _{2}$ gas.
The correct answer is

• A. Statement (A) is correct, but (B) is wrong.
• B. Both the statements are correct.
• C. Statement (A) is wrong, but (B) is correct.
• D. Both the statements are wrong.

Answer 1

Answer: (A)

Statement (A) Sulphur vapour is paramagnetic is correct statement as sulphur vapour has formula $S _{2}$, i.e. similar to $O _{2}$ and $O _{2}$ has two unpaired electrons in its anti-bonding molecular orbitals.

Statement (B) Reaction of $HCl \text{(dil.)}$ with finely divided iron forms $FeCl _{3}$ and $H _{2}$ gas is a wrong statement as the whole reaction is as follows:

$Fe +2 HCl \text {(dil.)} \longrightarrow FeCl _{2}+ H _{2}(g)$

The $H _{2}(g)$ produced will prevent the formation of $Fe ^{3+}$ (i.e. $\left.FeCl _{3}\right)$