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Q. Statement 1 : The variance of first n odd natural numbers is $\frac{n^{2}-1}{3}$
Statement 2: The sum of first n odd natural number is $n^2$ and the sum of square of first n odd natural numbers is $\frac{n\left(4n^{2}-1\right)}{3}.$

AIEEEAIEEE 2012Statistics

Solution:

Statement 2 : Sum of first n odd natural numbers is not equal to $n^2$.
So, statement - 2 is false.