Question

Statement 1: The highest manganese fluoride is $MnF_4$ and the highest oxide is $Mn_2O_7?$
Statement 2: In $Mn_2O_7,$ each $Mn$ is tetrahedrally surrounded by $Os$ including $Mn-O-Mn$ bridge

• A. If both Statement 1 and Statement 2 are true and the statement 2 is the correct explanation o f the statement 1.
• B. If both Statement 1 and Statement 2 are true but statement 2 is not the correct explanation o f the statement 1.
• C. If Statement 1 is true but Statement 2 is false.
• D. If Statement 1 is false but Statement 2 is true

Answer 1

Answer: (B)

Manganese with fluorine forms $MnF_4$ in highest oxidation state because of high electronegativity of fluorine

Oxygen forms multiple bonds to metals which explain its superiority over fluorine.