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Q. Statement 1:The green manganate is paramagnetic but the purple permanganate is diamagnetic in nature.
Statement 2: $MnO^{2-}_4$ contains one unpaired electron while in $MnO^{-}_4$ all electrons are paired

The d-and f-Block Elements

Solution:

Statement 1: Correct statement and reason is correct explanation of assertion.
Green $\to MnO^{2-}_{4}-\left[Ar\right]^{18} 3d^{1} 4s^{0}$ there is one unpaired electron, so paramagnetic.
Purple $\to MnO^{2-}_{4}-\left[Ar\right]^{18} 3d^{0} 4s^{0}$ here all electrons are paired, so diamagnetic