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Q. Statement 1: The equilibrium constant may show higher or lower values with increase in temperature
Statement 2: The change depends on the heat of reaction at equilibrium.

Equilibrium

Solution:

$2.303 log \frac{K_{c_2}}{K_{c_1}}=\frac{\Delta H}{R}\frac{\left[T_{2}-T_{1}\right]}{T_{1}T_{2}};$
if $\Delta H=-ve, K_{c_2} < K_{c_1}$ if $\Delta H=+ve, K_{c_2} > K_{c_1}.$