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Q. Statement 1 : $SO_2, NO_3^-$ and $CO_3^{2-}$ are isoelectronic as well as isostructural species
Statement 2 : The $d$and $d$ -orbitals do not shield the nuclear charge very effectively. Therefore, there is significant reduction in the size of the ions, just after $d$ or $f$ orbitals have been completely filled.

Chemical Bonding and Molecular Structure

Solution:

$S_1: SO_2, NO_3$ and $CO^{2-}_{3}$ have same number of electrons (i.e. $32$) but have different molecular geometry
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$S_2$ : The $d$- and $f$ orbitals do not shield the nuclear charge very effectively. Therefore, there is significant reduction in the size of the ions, just after $d$ or $f$ orbitals have been completely filled. This is called lanthanide contraction.