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Q. Statement 1:$PbI_{4}$ is a stable compound
Statement 2: $Pb^{2+}$ ions with concentrated solution of $KI$ forms a soluble complex

The p-Block Elements

Solution:

Statement 1: $Pb^{+4} \xrightarrow{+2e} Pb^{2+}$ (due to inert pair effect)
$2I^{-} \xrightarrow{I_{2}} (I^{-}$ acts as a reducing agent) so $PbI_{4}$ is not a stable compound.
Statement 2: $Pb^{2+} + 4I^{-} \to [PbI_{4}]^{-}$