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Q.
Statement 1: $O _2$ is a stronger reducing agent than $F _2$ Statement 2: $ F _2$ is more electronegative
Redox Reactions
Solution:
Correct (A): $F _2$ is a stronger oxidizing agent than $O _2$. Since reduction potential of $F _2 / 2 F ^{\ominus}$ is greater than the reduction potential ofO $O _2 / 2 O ^{2-}$. Moreover, $F _2$ oxidises
$H _2 O$ to $O _2$
$2 F _2( g )+2 H _2 O (l)\longrightarrow 4 H ^{\oplus}( aq )+4 F ^{\ominus}( aq )+ O _2( g )$