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Q. Statement 1: N atom has two different oxidation states in $NH_{4}NO_{2}$.
Statement 2: One N atom has -ve oxidation number as it is attached with less electronegative H atom and other has +ve oxidation number as it is attached with more electronegative atom.

Redox Reactions

Solution:

N in $NH_{4}^{+}$ is in $-3$ oxidation state and in $NO^{-}_{2}$ it is $+3 $ oxidation state.