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Q. Statement 1: Ions with more than five $3 d$ electrons have usually slightly larger magnetic moment than calculated on the basis of $\mu=\sqrt{n(n+2)}$
Statement 2: The maximum number of unpaired $d$-electrons is five as in $Mn ^{2+}$ and $Fe ^{3+}$ and so, $\mu=$ $5.92$ for $5$ unpaired electrons

Coordination Compounds

Solution:

The slightly larger value of $\mu$ than expected from the formula $\mu=\sqrt{n(n+2)}$ is due to a small contribution from the orbital anguler momentum of the electrons to the magnetic moment