Q.
Statement-1 : If $P\left(\frac{3 \sqrt{3}}{2}, 1\right)$ is a point on the ellipse $4 x^2+9 y^2=36$. Circle drawn AP as diameter touches another circle $x^2+y^2=9$, where $A \equiv(-\sqrt{5}, 0)$.
Statement-2 : Circle drawn with focal radius as diameter touches the auxiliary circle.
Conic Sections
Solution: