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Q. Statement-1: If in a triangle orthocentre, circumcentre and centroid are rational points then its vertices must also be rational points. because
Statement-2: If the vertices of a triangle are rational point then the centroid, circumcentre and orthocentre are also rational points.

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Solution:

$ S -2$ is obviously correct.
For statement-1: Let the circumcentre be at $(0,0)$ and the vertices of the triangle be $\left(x_1, y_1\right),\left(x_2, y_2\right)$ and $\left(x_3, y_3\right)$ then centroid is $\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}$ and orthocenre of the triangles becomes $\left( x _1+ x _2+ x _3, y _1+ y _2+ y _3\right)$.
This implies that if the centroid is rational then orthocentre is also rational but $\left(x_1+x_2+x_3\right)$ can be rational even if $x _1, x _2, x _3$ are not all rational.
e.g. $A (1,0) ; B (-1 / 2, \sqrt{3} / 2) ; C (-1 / 2,-\sqrt{3} / 2)$ where $G / H / C \cdot C$ are at $(0,0)$ i.e. rational points