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Q. Statement 1 : $HF$ forms two series of salts but $HCl$ not.
Statement 2 : $F$-atom is more electronegative than $Cl$- atom.

The p-Block Elements - Part2

Solution:

$HF$ forms $NaHF_2$ and $NaF$ salt due to its dimerised formula $H_2F_2$ on account of $H$-bonding. No doubt $F$ is more electronegative than $Cl$.