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Q. Statement 1: For the Daniell cell $Zn | Zn^{2+} || Cu^{2+} |$ Cu with $E_{cel|} = 1.1 V,$ the application of opposite potential greater than 1.1 V results into flow of electron from Cu to Zn.
Statement 2: Zn is deposited at anode and Cu is deposited at cathode.

Electrochemistry

Solution:

$Zn$ is -ve electrode and $Cu$ is +ve electrode in Daniel cell.