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Q. Statement 1: $\left[ Cr \left( NH _3\right)_6\right]^{3+}$ is paramagnetic.
Statement 2: $\left[ Cr \left( NH _3\right)_6\right]^{3+}$ shows $d^2 s p^3$ hybridisation.

Coordination Compounds

Solution:

The $Cr ^{3+}$ ions has three unpaired electrons. It has $d^2 s p^3$ hybridisation and it is paramagnetic.