1. Tardigrade
  2. Question
  3. Chemistry
  4. Statement-1: Aniline on reaction with NaNO2/HCl at 0° C followed by coupling with β-naphthol gives a dark blue coloured precipitate. Statement-2: The colour of the compound formed in the reaction of aniline with NaNO2/HCl at 0°C followed by coupling with p-naphthol is due to the extended conjugation.

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Q. Statement-1 : Aniline on reaction with $NaNO_2/HCl$ at $0^\circ C$ followed by coupling with $\beta$-naphthol gives a dark blue coloured precipitate.
Statement-2 : The colour of the compound formed in the reaction of aniline with $NaNO_2/HCl$ at $0°C$ followed by coupling with p-naphthol is due to the extended conjugation.

IIT JEEIIT JEE 2008Amines

Solution:

$C_6H_5NH_2 + NaNO_2/HCl\xrightarrow {0^{\circ}C} C_6H_5N^+_2 Cl^-$

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