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Q. Statement 1: $AlCl_{3}$ forms dimer $Al_{2}Cl_{6}$ in gaseous state but it dissolves in $H_{2}O$ forming $[Al(H_{2}O )_{6}]^{3+}$ and $3Cl^{-}$ ions.
Statement 2: Aqueous solution of $AlCl_{3}$ is acidic due to hydrolysis.

The p-Block Elements

Solution:

Statement 1: In gaseous phase and in non-polar solvent like benzene $AlCl_{3}$ exists as dimer, $Al_{2}Cl_{6}.$ High enthalpy of hydration in water breaks the covalent dimer forming $[Al(H_{2}O)_{6}]^{3+}$ and $3Cl^{-}$
Statement 2: $AlCl_{3} + 3H_{2}O \to Al(OH)_{3} + 3HCl$