Question

Statement 1: A plot of stopping potential $\left(V_{s}\right)$ vs frequency $(v)$ for different metals, has greater slope for metals with greater work functions.
Statement 2 : As work function increases, it requires greater energy to extricate the electrons from the surfaçe of their metals.

• A. Statement $-1$ is true, Statement $-2$ is false
• B. Statement $-1$ is false, Statement $-2$ is true
• C. Statement $-1$ is true, Statement $-2$ is true and Statement $-2$ is a correct explanation for Statement $-1.$
• D. Statement $-1$ is true, Statement $-2$ is true but Statement $-2$ is not a correct explanation for Statement $-1.$

Answer 1

Answer: (B)

Statement $- 1$ is false, Statement $- 2$ is true.
$e V_{s}=h v-W$
$V_{s}=\left(\frac{h}{e}\right) v-\left(\frac{W}{e}\right)$
For $V_{s}$ vs $v$ graph, slope $=\frac{h}{e}=$ constant.