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Q. Statement 1: $2$-Bromobutane on reaction with sodium ethoxide in ethanol gives $2$-butene as a major product.
Statement 2: $2$-Butene is more stable than $1$-butene.

Hydrocarbons

Solution:

$2$-bromobutane on reaction with sodium ethoxide in ethanol gives $2$-butene as a major product.
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This is according to Saytzeff's rale, i.e., the predominant product is the most substituted alkene, i.e. are carrying the largest number of alkyl substituents of hydrogen is eliminated preferentially from the carbon atom joined to the least number of hydrogen atoms.
$2$-butene is more stable than $1$-butene due to presence of large number of hyperconjugating structures in $2$-butene.