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  3. Chemistry
  4. Starting from propanoic acid, the following reactions were carried out Propanoic acid ->[SOCl2]X->[NH3]Y->[Br2+KOH]Z What is the compound Z?

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Q. Starting from propanoic acid, the following reactions were carried out
Propanoic acid
$\ce{->[SOCl_2]X->[NH_3]Y->[Br_2+KOH]Z}$
What is the compound $Z$?

VITEEEVITEEE 2019

Solution:

$\ce{CH3CH2COOH->[SOCl_2]CH3CH2COCl +SO2 +HCl}$
$\ce{CH CH CONH2+Br2/NaOH->}$$\underset{\text{Ethylamine, (Z)}}{\ce{CH3CH2NH2}}$$\ce{+ CO2}$

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