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Q. Standing waves are produced in a string $16 \,m$ long. If there are $9$ nodes between the two fixed ends of the string and the speed of the wave is $32 \,m / s$, what is the frequency of the Wave?

TS EAMCET 2019

Solution:

Given, length of spring, $l=16 \,m$
speed of wave, $v=32\, m / s$
and total number of nodes between the two fixed ends of the string $=9$
$\therefore $ Total number of segments of vibrations between fixed ends, $p=9+1=10$
$\therefore $ frequency of the wave, $f=\frac{p}{2 L} \times v$
$=\frac{10}{2 \times 16} \times 32=10 \,Hz$