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  4. Standard free energy change for an equilibrium is zero, the value of Kp is

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Q. Standard free energy change for an equilibrium is zero, the value of $K_{p}$ is

Haryana PMTHaryana PMT 2009Equilibrium

Solution:

Standard free energy change,
$\Delta G^{o}=-2.303 R T \log K_{p}$ If $\Delta G^{o}=0$
$\Rightarrow $ $0=-2.303 R T \log K_{p} \log K_{p}=0$
$\therefore K_{p}=1$