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Q. Standard electrode potential of cell $H_{2} | H^{+} || Ag^{+} | Ag$ is

Electrochemistry

Solution:

$\frac{1}{2}H_{2}|H{+} || Ag^{+}|Ag|$
$E^{o}_{cell} = E^{°}_{cathode} - E^{°} _{anode} = E^{°}_{Ag^{+}/Ag} - E^{°} _{H^{+}/ \frac{1}{2}H_[2}$
$(0.80)-(0.0) = 0.80\, V$